1214A - Optimal Currency Exchange - CodeForces Solution

brute force math *1400

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Python Code: 

n=int(input())
d=int(input())
e=int(input())*5
q=n//e
ans=n
for i in range(q+1):
    h=(n-i*e)%d
    ans=min(ans,h)
print(ans)

C++ Code: 

#include <cstdio>
typedef long long ll;

int main(){

    ll n; scanf("%lld", &n);
    ll d, h; scanf("%lld %lld", &d, &h);
    h *= 5;
    ll mn(n);
    for(ll p = 0; p * h <= n; p++){
        ll rem = (n - p * h) % d;
        mn = (mn < rem) ? mn : rem;
    }

    printf("%lld\n", mn);

    return 0;
}


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